yg bisa jawab gua kasi gopay 50k
Jawaban:
1.
Bila hambatan lampu sama = R
lampu 1 dan 2 diseri, hambatan penggantinya
Rs = R + R = 2R
Rs dan lampu 3 dan 4 diparalel
1/Rp = 1/Rs + 1/R + 1/R = 1/2R + 2/R = 1/2R + 4/2R = 5/2R
Rp = 2R/5
Tegangan di lampu 1,2,3,4 sama krn paralel
Vp = IRp = I x 2R/5 = I 2R/5
Ia = Vp/Rs = I 2R/5 / 2R = I/5
Ib = Vp/R = I 2R/5 /R = 2I/5
Ic = Vp/R = I 2R/5 /R = 2I/5
terlihat Ia arus terkecil maka lampu 1 dan 2 paling redup
2.
R2 dan 3 diseri
Rs = 4+8 = 12
Rs dan R1 diparalel
1/Rp = 1/Rs + 1/8 = 1/12 + 1/8 = 2/24 + 3/24 = 5/24
Rp = 24/5
Vab = I Rp = 4 x 24/5 = 19,2 volt
*maaf klo salah
*biasakan cari jawaban lain utk dibandingkan
Penjelasan:
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